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sched: Remove useless code in yield_to()
It's impossible to enter the else branch if we have set skip_clock_update in task_yield_fair(), as yield_to_task_fair() will directly return true after invoke task_yield_fair(). Signed-off-by: Michael Wang <wangyun@linux.vnet.ibm.com> Acked-by: Mike Galbraith <efault@gmx.de> Signed-off-by: Peter Zijlstra <a.p.zijlstra@chello.nl> Link: http://lkml.kernel.org/r/4FF2925A.9060005@linux.vnet.ibm.com Signed-off-by: Ingo Molnar <mingo@kernel.org>
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