mirror of
https://git.kernel.org/pub/scm/linux/kernel/git/stable/linux.git/
synced 2026-11-10 20:48:12 +00:00
btrfs: skip hole detection during full fsync for files without holes
If we the no-holes feature is enabled (a default since btrfs-progs 5.15),
when doing a full fsync we always iterate of all leaves in the subvolume
root that contain file extent items in order to detect holes between them.
This can take a lot of time for files with a large number of extents.
But if we know there are no prealloc extents and the amount of space
(uncompressed space) is greater than or equals to the i_size of the
inode, then we cannot have holes and therefore avoid searching for
them. So skip the search if those conditions are met.
The following test script was used:
$ cat test.sh
#!/bin/bash
MNT=/mnt/nullb0
DEV=/dev/nullb0
umount $MNT &> /dev/null
mkfs.btrfs -f $DEV
mount $DEV $MNT
# 256M gives 64K extents of 4K each.
FILE_SIZE=$((256 * 1024 * 1024))
touch $MNT/foobar
for ((i = 0; i < $FILE_SIZE; i += 8192)); do
xfs_io -c "pwrite -S 0xab $i 4K" $MNT/foobar > /dev/null
done
xfs_io -c "fsync" $MNT/foobar
for ((i = 4096; i < $FILE_SIZE; i += 8192)); do
xfs_io -c "pwrite -S 0xab $i 4K" $MNT/foobar > /dev/null
done
# unmount and mount, clear caches and ensure the next fsync is a
# full sync.
umount $MNT
mount $DEV $MNT
# Do some change to the file in order to fsync.
xfs_io -c "pwrite -S 0xcd 0 4K" $MNT/foobar > /dev/null
T0=$(date +%s%N)
xfs_io -c "fsync" $MNT/foobar
T1=$(date +%s%N)
echo
echo "Took $(( (T1 - T0) / 1000 ))us"
umount $MNT
Before this change:
Took 28721us
After this change:
Took 5453us
That's about 5.3x times faster.
Reviewed-by: Qu Wenruo <wqu@suse.com>
Signed-off-by: Filipe Manana <fdmanana@suse.com>
Signed-off-by: David Sterba <dsterba@suse.com>
This commit is contained in:
parent
6003c20dbd
commit
4096e2a06f
1 changed files with 9 additions and 0 deletions
Loading…
Add table
Add a link
Reference in a new issue